0:24Shorts

How To Get Stuff For CHEAPER #Shorts

United StatesPublished March 10, 2021

Views 675KΒ  | Β Likes 35.0KΒ  | Β Comments 265
Views#4,279,889Global
Views#920,609United States

Channel

ZhongZhong
80.6M subsβ€’2.54K videosβ€’Jan 2015

This video has 675K views and 35.0K likes, ranking #4,279,889 globally among tracked YouTube videos by view count.

At a glance

Views

675,562

Likes

35,032

Comments

265

Performance vs. channel

Outlier score

Engagement rate

Revenue estimate

Details β†’

Total (all-time): $473 – $1.35K

Based on estimated $0.7–$2 CPM.

About

make sure to subscribe !! road to 2m πŸ₯Ίβ€οΈ come back for daily uploads!! join the journey with me and my friends love you all #Shorts​​​​​​​​​​​​​​ make sure to follow me on all platforms instagram - @zhong snapchat - ZhongSnap tiktok - @Zhong

Published
March 10, 2021
Made for kids
No

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Frequently asked questions

How accurate are these YouTube video analytics?

View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.

What is the outlier score?

How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.

What is engagement rate and how is it calculated?

Likes and comments per view, compared to this channel's typical engagement rate β€” shown as above or below what's usual for the channel.

How is the revenue estimate calculated?

It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count β€” not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.

Is this YouTube video analytics checker free?

Yes. You get 10 free channel and video analytics lookups per rolling hour without an account β€” logging in, which is also free, removes that limit entirely.