3:42Long-form

Official Peet Montzingo TikTok Compilation Video 1

Published July 9, 2020

Views 2.16M  |  Likes 58.2K  |  Comments 1.33K
Views#1,344,798Global
Views#249,855Unknown country

Channel

Peet MontzingoPeet Montzingo
22M subs•654 videos•Jun 2014

This video has 2.16M views and 58.2K likes, ranking #1,344,798 globally among tracked YouTube videos by view count.

At a glance

Views

2,161,246

Likes

58,256

Comments

1,338

Performance vs. channel

Outlier score

Engagement rate

Revenue estimate

Details →

Total (all-time): $1.51K – $4.32K

Based on estimated $0.7–$2 CPM.

About

The official Peet Montzingo compilation video (Part 1)! Socials: https://www.tiktok.com/@peetmontzingo https://www.instagram.com/peet5west https://www.twitter.com/peet5west

Published
July 9, 2020
Made for kids
No

More features coming

We're working on new analytics and tools. Stay tuned.

Frequently asked questions

How accurate are these YouTube video analytics?

View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.

What is the outlier score?

How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.

What is engagement rate and how is it calculated?

Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.

How is the revenue estimate calculated?

It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.

Is this YouTube video analytics checker free?

Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.