보기만 보고 문제 풀기
Published November 25, 2024
At a glance
Views
116,721
Likes
1,834
Comments
68
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
#코믹숏무비 #너덜트 #nerdult #심리전 #수능 너덜트 공식 인스타그램 https://www.instagram.com/nerd_ult ※ 풀영상은 채널명 하단 영상의 제목을 눌러주세요
- Published
- November 25, 2024
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How 보기만 보고 문제 풀기 is doing
It has 116K views in total. It ranks #11,599,937 among tracked YouTube videos by views.
Key facts about 보기만 보고 문제 풀기
- Total views
- 116K
- Total likes
- 1.83K
- Total comments
- 68
- Published
- November 25, 2024
- Global rank by views
- #11,599,937
Frequently asked questions
How many views does 보기만 보고 문제 풀기 have?
보기만 보고 문제 풀기 has 116,721 views, 1,834 likes and 68 comments, ranking #11,599,937 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.