Asking woman how she got so fit.
Published September 30, 2026
At a glance
Views
187,349
Likes
3,275
Comments
260
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
- Published
- September 30, 2026
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How Asking woman how she got so fit. is doing
It has 187K views in total. It ranks #10,293,491 among tracked YouTube videos by views.
Key facts about Asking woman how she got so fit.
- Total views
- 187K
- Total likes
- 3.27K
- Total comments
- 260
- Published
- September 30, 2026
- Global rank by views
- #10,293,491
Frequently asked questions
How many views does Asking woman how she got so fit. have?
Asking woman how she got so fit. has 187,349 views, 3,275 likes and 260 comments, ranking #10,293,491 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.