2009-05-20 完全娱樂~孫燕姿蔡依林 演唱會合作好好看！
Published May 24, 2009
At a glance
Views
16,544
Likes
26
Comments
2
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
2009-05-20 完全娱樂~孫燕姿蔡依林 演唱會合作好好看！
- Published
- May 24, 2009
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How 2009-05-20 完全娱樂~孫燕姿蔡依林 演唱會合作好好看！ is doing
It has 16.5K views in total. It ranks #13,392,232 among tracked YouTube videos by views.
Key facts about 2009-05-20 完全娱樂~孫燕姿蔡依林 演唱會合作好好看！
- Total views
- 16.5K
- Total likes
- 26
- Total comments
- 2
- Published
- May 24, 2009
- Global rank by views
- #13,392,232
Frequently asked questions
How many views does 2009-05-20 完全娱樂~孫燕姿蔡依林 演唱會合作好好看！ have?
2009-05-20 完全娱樂~孫燕姿蔡依林 演唱會合作好好看！ has 16,544 views, 26 likes and 2 comments, ranking #13,392,232 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.