[ NCT 도영 ] 당신이 원하는 강사는 누구?
Published October 31, 2026
At a glance
Views
13,885
Likes
1,080
Comments
15
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
#엔시티 #엔시티127 #NCT #NCT127 #도영 #DOYOUNG
- Published
- October 31, 2026
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How [ NCT 도영 ] 당신이 원하는 강사는 누구? is doing
It has 13.8K views in total. It ranks #15,513,414 among tracked YouTube videos by views.
Key facts about [ NCT 도영 ] 당신이 원하는 강사는 누구?
- Total views
- 13.8K
- Total likes
- 1.08K
- Total comments
- 15
- Published
- October 31, 2026
- Global rank by views
- #15,513,414
Frequently asked questions
How many views does [ NCT 도영 ] 당신이 원하는 강사는 누구? have?
[ NCT 도영 ] 당신이 원하는 강사는 누구? has 13,885 views, 1,080 likes and 15 comments, ranking #15,513,414 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.