3:43:53Long-form

一口气看完,【宝可梦POKEMON】1-6部全系列,小智25年夺冠路!

Hong Kong SAR ChinaPublished January 8, 2023

Views 1.38M  |  Likes 7.74K  |  Comments 346
Views#2,552,275Global
Views#2,220Hong Kong SAR China

Channel

芙芙家的洗碗君芙芙家的洗碗君
180K subs•527 videos•Aug 2020

This video has 1.38M views and 7.74K likes, ranking #2,552,275 globally among tracked YouTube videos by view count.

At a glance

Views

1,387,074

Likes

7,743

Comments

346

Performance vs. channel

Outlier score

Engagement rate

Revenue estimate

Details →

Total (all-time): $971 – $2.77K

Based on estimated $0.7–$2 CPM.

About

求订阅!!!求订阅!!!超多热门动漫全系列解说,死火海妖七龙珠全都有!! 海贼王1-1100集解说:https://youtu.be/Fy9x6KAd6T8 在哔哩哔哩有全系列完整视频,欢迎前来观看 欢迎关注来B站UP主:芙芙家的洗碗君 https://space.bilibili.com/4925207?spm_id_from=333.337.0.0

Published
January 8, 2023
Made for kids
No

More features coming

We're working on new analytics and tools. Stay tuned.

Frequently asked questions

How accurate are these YouTube video analytics?

View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.

What is the outlier score?

How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.

What is engagement rate and how is it calculated?

Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.

How is the revenue estimate calculated?

It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.

Is this YouTube video analytics checker free?

Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.