#Shorts | BUSCÁNDONOS en GOOGLE
Published October 23, 2026
At a glance
Views
54,005
Likes
4,267
Comments
41
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
Shorts, funny
- Published
- October 23, 2026
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How #Shorts | BUSCÁNDONOS en GOOGLE is doing
It has 54.0K views in total. It ranks #13,680,165 among tracked YouTube videos by views.
Key facts about #Shorts | BUSCÁNDONOS en GOOGLE
- Total views
- 54.0K
- Total likes
- 4.26K
- Total comments
- 41
- Published
- October 23, 2026
- Global rank by views
- #13,680,165
Frequently asked questions
How many views does #Shorts | BUSCÁNDONOS en GOOGLE have?
#Shorts | BUSCÁNDONOS en GOOGLE has 54,005 views, 4,267 likes and 41 comments, ranking #13,680,165 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.