그녀석에게 버거킹을 보여선 안돼
Published April 3, 2022
At a glance
Views
187,540
Likes
3,872
Comments
162
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
#Shorts #버거킹 #맥도날드 인스타: https://www.instagram.com/yeongmin0917/?hl=ko 이메일: [email protected]
- Published
- April 3, 2022
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How 그녀석에게 버거킹을 보여선 안돼 is doing
It has 187K views in total. It ranks #7,855,505 among tracked YouTube videos by views.
Key facts about 그녀석에게 버거킹을 보여선 안돼
- Total views
- 187K
- Total likes
- 3.87K
- Total comments
- 162
- Published
- April 3, 2022
- Global rank by views
- #7,855,505
Frequently asked questions
How many views does 그녀석에게 버거킹을 보여선 안돼 have?
그녀석에게 버거킹을 보여선 안돼 has 187,540 views, 3,872 likes and 162 comments, ranking #7,855,505 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.