No passing by Minjae 🥶💪
Published May 15, 2026
At a glance
Views
254,741
Likes
6,490
Comments
59
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
This run by Minjae Kim in the Bundesliga vs Köln was insane! #shorts
- Published
- May 15, 2026
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How No passing by Minjae 🥶💪 is doing
It has 254K views in total. It ranks #9,099,976 among tracked YouTube videos by views.
Key facts about No passing by Minjae 🥶💪
- Total views
- 254K
- Total likes
- 6.49K
- Total comments
- 59
- Published
- May 15, 2026
- Global rank by views
- #9,099,976
Frequently asked questions
How many views does No passing by Minjae 🥶💪 have?
No passing by Minjae 🥶💪 has 254,741 views, 6,490 likes and 59 comments, ranking #9,099,976 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.