
크리스토퍼 놀란 오디세이 보기 전에
Published August 6, 2026
At a glance
Views
143,080
Likes
680
Comments
9
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
#오디세이 #문쌤 #크리스토퍼놀란 크리스토퍼 놀란 감독의 영화 오디세이 개봉을 맞아, 오디세우스의 모험담을 설명해주는 문쌤. 그런데 비유가 어딘가 이상하다.
- Published
- August 6, 2026
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How 크리스토퍼 놀란 오디세이 보기 전에 is doing
It has 143K views in total. It ranks #10,833,440 among tracked YouTube videos by views.
Key facts about 크리스토퍼 놀란 오디세이 보기 전에
- Total views
- 143K
- Total likes
- 680
- Total comments
- 9
- Published
- August 6, 2026
- Global rank by views
- #10,833,440
Frequently asked questions
How many views does 크리스토퍼 놀란 오디세이 보기 전에 have?
크리스토퍼 놀란 오디세이 보기 전에 has 143,080 views, 680 likes and 9 comments, ranking #10,833,440 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.